y = = 1 D(y) = (– ; 2) (2; + ) 2 x = 2 – точка разрыва = + = + x = 2 – вертикальная асимптота 3 y = kx + b k = = = = = = = = 0 b = (–) = = = = = = 1 y = 1 при x 4 непериодическая 5 f(–x) = = f(x) – f(x) 6 y = 0 = 0 = 0 D = 16 – 16 = 0 x = – 2 пересечение с OY y(0) = 1; пересечение с OX x = – 2 > 0 y > 0 при x (– ; – 2)( –2; 2)(2; + ) 7 y= = = = = = = = y= 0; = 0 x = – 2 y не существует при x = 2
(– ; – 2)
–2
(–2; 2)
(2; + )
y
–
0
+
8 y= = = 16x+64 = 0 16x = – 64 x = – 4 y не существует при x = 2
x
(– ; – 4)
– 4
(–4; 2)
1/9
9 E(y) = (0; + ) 10
–3
–1
1
3
4
6
8
10
1/15
9
15
2,8
2,25
= 
; 2)
(2; + 
)
= + 
= + 
=
= 
=
= 
=
= 0
(
–
) = 
= 
=
= 
= 
= 1
= 
f(x)
– f(x) 
= 0
= 0 
> 0 
(– 
; – 2)
( –2; 2)
(2; + 
)
= 
= 
= 
= 
= 
= 
= 0; 
= 0
не существует при x = 2
; – 2)
)
= 
= 
= 
не существует при x = 2 
; – 4) 
) 
)